In triangle ABC, let E be the midpoint of altitude AD from A to BC. The excircle opposite C is tangent to BC at G, and line EG intersects the excircle at H. Prove that HG bisects angle BHC.
In triangle's grace,
Midpoint, altitude, and excircle,
Bisectors reveal.
Key Term | Description |
---|---|
Triangle | The geometric figure ABC, consisting of three sides and three angles. |
Altitude | The perpendicular segment AD from vertex A to side BC in triangle ABC. |
Midpoint | The point E that divides the altitude AD into two equal segments. |
Excircle | The circle opposite vertex C that is tangent to side BC of triangle ABC at point G. |
Tangency Point | Point G where the excircle opposite C is tangent to BC. |
Perpendicular | The line segment AD, which is perpendicular to side BC of triangle ABC. |
Intersection | The point H where line EG intersects the excircle opposite C. |
Angle Bisector | The line HG that bisects angle BHC in the geometric problem. |
Bisects Angle | To divide an angle into two equal parts. In this problem, line HG bisects angle BHC. |
Geometry Problems
Open Problems
Visual Index
All Problems
Triangles
Altitude
Midpoint
Circle
Triangle Centers
Excircle
Secant to a Circle
Circle Tangent Line
Angle
Angle Bisector
Perpendicular lines
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