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In a triangle ABC (see the figure below), the incircle of center I is tangent to BC, AC, and AB at D, E, and F, respectively. BI extended meets DE at G. Prove that angle C = 2 angle IFG.

Home | Search | Geometry | Problems | All Problems | Open Problems | Visual Index | 10 Problems | 1051-1060 | Triangle | Incenter, incircle | Circle | Tangent Line | Angle | Angle Bisector | Email | Solution / comment | by Antonio Gutierrez Last updated: Nov 15, 2014