Geometry, Theorems and Problems

Problem 207: Prove the Fascinating Link Between Hypotenuse, Exradius, and Inradius in Right Triangles!. Level: High School, SAT Prep, College Geometry

In the figure below, BAC is a right triangle of hypotenuse BC = a. If r is the inradius, ra is the exradius relative to the hypotenuse, and the points D, E, F, and G are the points of tangency, prove that: a = DG = EF = ra - r.
View or post a solution.
 

Right triangle, hypotenuse
 

Flyer of problem 207 using iPad Apps

Flyer of problem 207 involving relationship for the hypotenuse, inradius and exradius in a right triangle using iPad App

Home | Geometry | Search | Problems | 201-210 | View or post a solution | Email