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Geometry Problem 642. Archimedes' Book of Lemmas: Proposition 3

Let C be any point on a semicircle of diameter AB, and let CD be perpendicular to AB. Take E on AB so that AD = DE. Take F on arc CB so that arc CF = arc AC. Prove BF = BE.
 

Archimedes Book of Lemmas: Semicircle, Tangent, Perpendicular
 
 


Books of Lemmas Index

Proposition 1
Proposition 2
Proposition 3
Proposition 4
Proposition 5
Proposition 6
Proposition 7
Proposition 8
Proposition 9
Proposition 10
Proposition 11
Proposition 12
Proposition 13
Proposition 14
Proposition 15

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