The figure below shows a triangle ABC,
medians AD, BE, CF, and centroid G. O1, O2, O3, O4 are the circumcenters of
triangles AFG, AGE, BGF, and BGD, respectively. O1O2 cuts O4O3
at H. CP is parallel to AD (P on BE extended). Prove
that HO3.CP = HO1.GP.

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