Four congruent circles of centers A, B, C, and D intersect as shown.
If P is
a point on the circle D, prove that PA^{2} = PB^{2} + PC^{2}.

Geometry Problems

Ten problems: 1401-1410

Visual Index

Open Problems

All Problems

Circle

Intersecting Circles

Congruence

Collinear Points

Equilateral Triangle

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