In a triangle ABC, X is a point on BC and AY is the bisector of the angle
CAX as shown in the figure. The circumcircle of the triangle ABX cuts AY
at Z. BZ extended meets AC at W. Prove that angle XBZ + angle WXZ = angle
XWY. *This entry contributed by Sumith Peiris, Moratuwa, Sri Lanka.*

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Ten problems: 1321-1330

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Sketch of problem 1322

Geometry Problems

Ten problems: 1321-1330

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