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The figure below shows a triangle ABC with the median AD perpendicular to median CE at H. Prove that BH = AC.
Home | Search | Geometry | Problems | All Problems | Open Problems | Visual Index | 10 Problems | 1051-1060 | Triangle | Midpoint | Median | Perpendicular lines | Congruence | Email | by Antonio Gutierrez
Add or view a solution to the problem 1053 Last updated: Dec 2, 2014