The figure below shows a quadrilateral ABCD with AC
perpendicular to BD, AE = DE, and BE = CE. FEG is perpendicular
to AB ( F on AB and G on BC extended), HDK is perpendicular to
AB (H on AB extended and K on BC extended). If BC = 7 and CG =
3, find BK.
![Geometry Problem 1041: Quadrilateral, Perpendicular, Diagonals, Congruence, Metric Relations](p1041-quadrilateral-perpendicular-diagonals-congruence-metric-relations-math.gif)
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