

Problem 540: Right Triangle, Square, Parallel, Perpendicular,
Dissection, Area, Pythagoras. Level: High School, SAT Prep, College

The figure shows a right triangle ACB with
the squares ABDE, ACJK (area A_{1}), and BCMN (area A_{2}). AG and DH are parallel to line CBF. Line EHG and DF are parallel
to AC. If A_{3} is the area of the
region ACFDHG, prove that A_{1} + A_{2} = A_{3}.
Post a comment or solution.







