Geometry
Problem 903: First
Fermat Point
The figure shows an acute triangle ABC
with three equilateral triangle erected externally on the sides.
Prove that (1) AA', BB', and CC' concur in a point F called the
Fermat point. (2)The angles AFB, BFC, and AFC are equal to 120
degrees. (3) AF + BF + CF is the minimum possible.

Recent Additions
