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Geometry Problem 1180: Quadrilateral, 120 Degrees, Diagonals, Perpendicular

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In a triangle ABC, angle A + angle D = 120 degrees, AC and BD meet at E and are the bisectors of angles A and D, respectively. Line FEG is perpendicular to BC (F on BC, G on AD). Prove that EG = 2EF.

  

Geometry Problem 1180: Quadrilateral, 120 Degrees, Diagonals, Perpendicular

 

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Last updated: Jan 16, 2016

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