Problem 398: Parallelogram, Area, Similarity, Congruence

Online Math. Activate Flash plug-in or JavaScript and reload to view problem about: Parallelogram, Area, Online Learning.

The figure shows a parallelogram ABCD of area S. AE = CF = AB/3, BG = DH = BC/3. Line CE intersects BH at M, and DG at N. Line AF intersects DG at P, and BH at Q. If S1 is the area of quadrilateral MNPQ, prove that S1 = S/13. .
 

Parallelogram Area
 

Home | SearchGeometry | Problems | Art | All Problems | 391-400 | Area of a Parallelogram | Email | Post a comment/solution