Problem Problem 334. Cyclic Quadrilateral, Perpendiculars to Diagonals. Level: High School, College, SAT Prep.

The figure shows a cyclic quadrilateral ABCD. E is the intersection point of AC and BD. AF and CH are perpendicular to BD. BG and DM are perpendicular to AC.
Prove that (1) AF.CH = BG.DM, (2) EF.EH = EG.EM. Post a comment.