In the figure below, ABC is a
triangle inscribed in a circle of center O (circumcenter) and
E is the center (excenter) of the excircle relative to side BC. Line
AE and the circumcircle meet at D. If R is the circumradius and r_{1}
is the exradius (radius of circle E), (1) prove that BD = DE, and (2) prove that
AE.DE = 2R.r_{1}.
View or post a solution.
