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In the figure below, given a triangle
ABC of area S, the medians BM and CN meet at G. Let be BD = 2 CD, the cevian AD meets BM and CN at E and F respectively.
Area of triangle EFG is S1. Prove that:
GE/EM = 2/3, GF/CF = 1/3 and S1 = S/60.
Post a comment or solution.
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FACTS AND HINTS:
Geometry problem solving is one of the most challenging skills for students to learn. When a
problem requires auxiliary construction, the difficulty of the problem increases drastically, perhaps because deciding which construction to make is an ill-structured problem. By “construction,” we mean adding geometric figures (points, lines, planes) to a problem figure that wasn’t mentioned as "given."
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