Problem 91. Similar Triangles, Altitude, Parallel,
Level: High School, College
In the figure below, given a triangle
ABC, an altitude AH = h, line DEF parallel to AC and line FGM
parallel to AB. If h1, h2, and h3
are perpendicular to BC respectively, prove that: h = h1
+ h2 + h3.
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FACTS AND HINTS:
1. SIMILAR TRIANGLES:
Corresponding segments of similar triangles are in proportion.