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Given a triangle ABC of area S, the
incircle of center I and inradius r. If AC = b and AB = c, prove
that
area of triangle DIE
.
Post a comment or solution.
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"A great discovery solves a great problem, but there is a grain
of discovery in the solution of any problem. Your problem may be
modest, but if it challenges your curiosity and brings into play
your inventive faculties, and if you solve it by your own means,
you may experience the tension and enjoy the triumph of
discovery. Such expert experiences at a susceptible age may
create a taste for mental work and leave their imprint on mind
and character for a lifetime." George Polya, 1944
HINTS:
CIRCLE is the set of all points in a plane that are
at the same distance from a fixed point called the center.
Tangent of a circle is a
line that touches the circle at one and only one point no
matter how far produced.
Proposition. If a line is tangent to a circle, it is
perpendicular to a radius at the point of tangency.

INCENTER of a triangle
Proposition: The
bisectors AD, BF and CE of the angles of a triangle ABC meet
in a point I, which is equidistant from the sides of the
triangle.
The incircle is the inscribed
circle of a triangle. The center of the incircle is called
the incenter, and the radius of the circle is called the
inradius.

PERPENDICULAR LINES AND ANGLES
Proposition: Two angles
are congruent or supplementary if their sides are
respectively perpendicular to each other.

AREA OF A TRIANGLE:
Proposition:
The area of a triangle equals
one-half the product of the length of a side and the length of
the altitude to that side.
Side Angle Side Formula: The
SAS formula = ½ (side1 × side2) × sine(included angle).


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